Last Activity: 11 Years ago
Ans. is 72!!
All letters are nt same so
There are 5 cases
• of form(abcde) all distinct = 6 ways
• of form (aaabb)= 4 ways
•of form( aaabc)= 5c2 +5c2= 20 ways
•of form (aabcd)= 3.5c3 = 30ways
•of form (aabbc) =3.4c1= 12ways
Adding these 72!!!
in given word 11 letters are present.in all of them 3-N,2-D,2-E are present.
so required answer is =(11!)÷(3!×2!×2!)
=1663200
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